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Force: Mathematical problem & solution-3

Problem 1: Force and Acceleration

Problem: A 5 kg object is subjected to a force that accelerates it at 3 m/s². Calculate the force applied.

Solution: Using Newton's second law, 𝐹=𝑚𝑎:

𝐹=5 kg×3 m/s2=15 N

The force applied is 15 N.

Problem 2: Force and Friction

Problem: A 10 kg box is being pushed across a horizontal surface with a coefficient of kinetic friction of 0.4. Calculate the force required to keep the box moving at a constant velocity.

Solution:

  1. Calculate the normal force (𝐹𝑁):
𝐹𝑁=𝑚𝑔=10 kg×9.8 m/s2=98 N
  1. Calculate the frictional force (𝐹𝑓):
𝐹𝑓=𝜇𝐹𝑁=0.4×98 N=39.2 N

The force required is 39.2 N.

Problem 3: Force in Circular Motion

Problem: A 2 kg object is whirled in a horizontal circle of radius 1 meter at a speed of 4 m/s. Calculate the centripetal force.

Solution: Using 𝐹𝑐=𝑚𝑣2𝑟:

𝐹𝑐=2 kg×(4 m/s)21 m=32 N

The centripetal force is 32 N.

Problem 4: Hooke's Law

Problem: A spring with a spring constant of 200 N/m is compressed by 0.05 meters. Calculate the force exerted by the spring.

Solution: Using Hooke's law, 𝐹=𝑘𝑥:

𝐹=200 N/m×0.05 m=10 N

The force exerted is 10 N.

Problem 5: Momentum Change

Problem: A 3 kg ball moving at 10 m/s is brought to rest in 2 seconds by a constant force. Calculate the force.

Solution:

  1. Calculate the change in momentum (Δ𝑝):
Δ𝑝=𝑚(𝑣𝑓𝑣𝑖)=3 kg×(010 m/s)=30 kg m/s
  1. Calculate the force (𝐹):
𝐹=Δ𝑝Δ𝑡=30 kg m/s2 s=15 N

The force is 15 N.

Problem 6: Work Done by Force

Problem: A 50 N force is applied to push a box 4 meters across a floor. Calculate the work done.

Solution: Using 𝑊=𝐹𝑑:

𝑊=50 N×4 m=200 J

The work done is 200 J.

Problem 7: Power Developed

Problem: A machine lifts a 500 kg object vertically at a constant speed of 2 m/s. Calculate the power developed.

Solution:

  1. Calculate the force (𝐹):
𝐹=𝑚𝑔=500 kg×9.8 m/s2=4900 N
  1. Calculate the power (𝑃):
𝑃=𝐹𝑣=4900 N×2 m/s=9800 W

The power developed is 9800 W.

Problem 8: Gravitational Force

Problem: Calculate the gravitational force between two 100 kg masses separated by 2 meters.

Solution: Using Newton's law of gravitation, 𝐹=𝐺𝑚1𝑚2𝑟2, where 𝐺=6.674×1011 N m2/kg2:

𝐹=6.674×1011 N m2/kg2×100 kg×100 kg(2 m)2=1.6685×108 N

The gravitational force is 1.6685×108 N.

Problem 9: Impulse

Problem: A 2 kg ball is hit by a bat, changing its velocity from 5 m/s to 10 m/s in 0.2 seconds. Calculate the impulse imparted to the ball.

Solution: Impulse (𝐽) is given by the change in momentum:

𝐽=Δ𝑝=𝑚(𝑣𝑓𝑣𝑖)=2 kg×(10 m/s5 m/s)=10 kg m/s

The impulse is 10 kg m/s.

Problem 10: Newton's Third Law

Problem: Two ice skaters, one with mass 70 kg and the other with mass 50 kg, push off each other. If the 70 kg skater moves at 2 m/s, calculate the velocity of the 50 kg skater.

Solution: Using conservation of momentum:

𝑚1𝑣1+𝑚2𝑣2=0

Given:

  • 𝑚1=70 kg
  • 𝑣1=2 m/s
  • 𝑚2=50 kg
  • 𝑣2=?
70 kg×2 m/s+50 kg×𝑣2=0
140 kg m/s+50 kg×𝑣2=0
𝑣2=140 kg m/s50 kg=2.8 m/s

The velocity of the 50 kg skater is 2.8 m/s in the opposite direction.

These problems cover a range of scenarios involving forces, providing a comprehensive review of how force is applied in different contexts.

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