Search This Blog

pCloud Crypto

Math solution on Mass & energy

The relationship between mass and energy is most famously expressed by Einstein's equation from his theory of relativity:

𝐸=𝑚𝑐2

where:

  • 𝐸 is the energy,
  • 𝑚 is the mass,
  • 𝑐 is the speed of light in a vacuum (𝑐3×108m/s).

This equation shows that mass can be converted into energy and vice versa. It has profound implications in fields such as nuclear physics, where small amounts of mass can be converted into large amounts of energy.

Example Problem

Let's solve an example problem step-by-step using this formula.

Problem

Calculate the energy equivalent of 1 gram of mass.

Solution

  1. Identify the given values:

    • Mass, 𝑚=1g=1×103kg (since 1g=0.001kg)
    • Speed of light, 𝑐=3×108m/s
  2. Substitute the values into the mass-energy equivalence formula:

    𝐸=𝑚𝑐2
    𝐸=(1×103kg)×(3×108m/s)2
  3. Calculate the term 𝑐2:

    𝑐2=(3×108m/s)2=9×1016m2/s2
  4. Continue with the calculation:

    𝐸=(1×103kg)×(9×1016m2/s2)
    𝐸=9×1013kgm2/s2=9×1013J

So, the energy equivalent of 1 gram of mass is 9×1013joules.

Conclusion

Using Einstein's mass-energy equivalence formula, we determined that 1 gram of mass is equivalent to 9×1013joules of energy. This enormous amount of energy from a small mass exemplifies why nuclear reactions, which convert mass into energy, can release such tremendous amounts of energy.

No comments:

Post a Comment

pCloud Lifetime

Popular Posts